2) Cuadro de aluminio 2x2cm m= 0.2g 28 cm de O₂
3) Cuadro de aluminio 2x2cm m= 0.1g 25 cm de O₂
4) Cuadro de aluminio 2x2cm m= 0.1 24 cm de O₂
5) Cuadro de aluminio 2x2cm m= 0.1g 25 cm de O₂
V= (πr^2)h
V=[π(3.8)^2]12
V= 544.37 cm cúbicos
(544.37)(.20)= 108.87
108.87 mL de O₂
∫= m/v
m= ∫.v
m= (0.001429mL)(544.37cm^3)
m= 0.77g O₂
∫= 0.001429mL
2H₂ + O₂ -------> 2H₂O
4g H₂ - 32g O₂
X - 0.77g O₂
X= 0.09712g H₂
∫= 0.00008988
V= m/∫
V= 1080.55 cm^3
______________________________________________________________________________
2Al + 6HCl --------> 3H2 + 2AlCl3
54gAl + 216gHCl -------> 6gH + 132 AlCl
54gAl -- 6gH
x -- 0.09711
x= 0.8739
900cm^3 --- 4g
x --- o.8739g
x= 14.06 cm
